[Free] Second Law Of Thermodynamics

Heat Engine, Heat Pump and Refrigeration system – Free Course

Added on August 23, 2023 Teaching & Academics 2 min read

What you’ll learn

To study the aspects of Second law of Thermodynamics
To understand the statements of Second law of thermodynamics
To get the concept of Equivalence of Kelvin-Planck and Clausius Statement
To get the idea of COP of Heat pumps and Refrigeration
To know the methods of solving numericals on Heat Engine, Heat Pump and Refrigerator
Get idea about Carnots theorem and Carnot Cycle.
Know the working principle of Heat Engines, Heat Pumps and Refrigerators .

Requirements

Engineering Physics , Engineering Chemistry, Basic Mechanical Engineering

Description

Course Contents as per syllabus :

Equivalence of Clausius and Kelvin Planck Statement, PMM I and II, Concept of Reversibility and Irreversibility.

Course Objectives:

To study the aspects of Second law of Thermodynamics

To understand the statements of Second law of thermodynamics

To get the concept of Equivalence of Kelvin-Planck and Clausius Statement

To define Perpetual Machine of IInd Kind (PMM-II)

To Study Carnot theorem and Carnot Cycle

To get the knowledge of Heat engine and its efficiency

To compare Heat pumps and Refrigeration system

To get the idea of COP of Heat pumps and Refrigeration

To know the methods of solving numericals on Heat Engine, Heat Pump and Refrigerator

Brief description about Heat Engine, Refrigerator and Heat pump :

HEAT ENGINE

Based on Kelvin- Plancks Statement.

It is a device that converts heat to work.

In case of heat engine, efficiency is defined as ratio of work done to heat energy supplied.

Here important criteria is net work done.

Work done by the engine =W = (Q1 Q2)

Efficiency = Work done / Heat supplied

Efficiency = W / Q1 = (Q1 Q2) / Q1

= (T1-T2 ) / T1

= 1 ( T2 / T1)

REFRIGERATOR

Based on Clausius Statement.

In case of a refrigerator ,COP is defined which is the ratio of heat absorbed (refrigeration effect) to work done on the system ,Here the important criteria is heat absorbed as refrigeration effect.

Work Done on system = (Q1 Q2)

COPR = Desired Effect / Work done

= Q2 / ( Q1 Q2)

= T2 / ( T1-T2)

COP is reverse of Efficiency

HEAT PUMP

Based on Clausius Statement.

In case of a heat pump ,COP is defined which is the ratio of heat rejected (refrigeration effect) to work done on the system. Here the important criteria is heat rejected as refrigeration effect.

Work Done on system = (Q1 Q2)

COPHP = Desired Effect / Work done

= Q1 / ( Q1 Q2)

= T1 / ( T1-T2)

COP HP = COPR + 1

Course Outcomes :

Learner will be able to

Get idea about limitations of First law of Thermodynamics.

Can compare between Kelvin and Clausius Statements.

Understand various statements of Second law of Thermodynamics.

Have clear idea about Kelvin and Clausius Statement.

Get idea about Carnots theorem and Carnot Cycle.